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9x^2=+6x+8=0
We move all terms to the left:
9x^2-(+6x+8)=0
We add all the numbers together, and all the variables
9x^2-(6x+8)=0
We get rid of parentheses
9x^2-6x-8=0
a = 9; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·9·(-8)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18}{2*9}=\frac{-12}{18} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18}{2*9}=\frac{24}{18} =1+1/3 $
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